## 题目描述

Chef found a strange string yesterday – a string of signs $s$, where each sign is either a ‘<‘, ‘=’ or a ‘>’. Let $N$ be the length of this string. Chef wants to insert $N+1$ positive integers into this sequence and make it valid. A valid sequence is a sequence where every sign is preceded and followed by an integer, and the signs are correct. That is, if a sign ‘<‘ is preceded by the integer $a$ and followed by an integer $b$, then $a$ should be less than $b$. Likewise for the other two signs as well.

Chef can take some positive integers in the range $[1, P]$ and use a number in the range as many times as he wants.

Help Chef find the minimum possible $P$ with which he can create a valid sequence.

## 题意概述

给定一个由'<‘、’=’和’>’组成的字符串，要求在首尾和每两个相邻的符号间填入一个数，使得表达式成立。求数字的最小种类数。

数据范围：$1 \le |s| \le 10^5$。

## 算法分析

将’=’删去后，计算出只由'<‘或’>’组成的最长连续子串的长度，加$1$即得到答案。证明如下：

‘=’对最终结果没有影响，可以全部忽略。设找到了一个只由'<‘或’>’组成的最长连续子串，长度为$l$。在这个子串的左边填入$a$，右边填入$a+l$。由于其他只由'<‘或’>’组成的连续子串的长度均不大于$l$，因此也可以分别在它们左右填入$a$和$a+l$，这样必定可以满足题目要求。

由此得证。

## 代码

#include <iostream> #include <algorithm> using namespace std; int n, ans, len, out; string s; int main() { cin >> n; while (n--) { cin >> s; ans = out = 0; len = s.length(); for (int i = 0; i < len; ++i) { if (s[i] == '<') { if (ans < 0) ans = 0; ++ans; } if (s[i] == '>') { if (ans > 0) ans = 0; --ans; } out = max(out, abs(ans) + 1); } cout << out << endl; } return 0; }